Wakulla County

Wakulla County, Florida

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Nestled in Florida is Wakulla, home to the city of Crawfordville. The population density is 51 people per square mile across the 606 square miles included by the County. The population in 2014 was estimated to be 31,432, and it expanded by 2.1 percent since 2010. Relative to Florida, Wakulla has an average number of young familes at 5 percent, an average number of children under 18 at 21 percent, and a less than average (17.3) number of retirees at 13 percent. Households often stay in place, with 80 percent staying in the same residence more than one year. Education statistics show that 17 percent of residents have a bachelor's degree or higher, while 88 percent finished secondary school.

Median Home Price
$ 138k
Houses: 12,838

There are approximately 10,455 households living in 12,838 homes, and 5 percent of these houses are in multi-unit buildings. The median price of properties is $138.3k, and the homeownership rate is 79 percent. The median household income is $52.7k, which is greater than that of the state. The County of Wakulla has a total of 2,750 businesses, and citizens have an average commute to work of 30 minutes.

MV Affordability Index
Business Sector Production
Median income and home price
Population Age Distribution

Largest Cities in Wakulla County

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MadValorem · Data provided by MV Realty